Calculus: Early Transcendentals - Instructor's Solution Manual (5th Edition)
James Stewart
Language: English
Pages: 1778
ISBN: 2:00044188
Format: PDF / Kindle (mobi) / ePub
In-Depth Solutions key to my previous upload, Calculus: Early Transcendentals Fifth Edition. Explains the methods to obtaining the answers for all odd and even problems. The perfect tool for learning Calculus 1-3. Enjoy.
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Graph 2 2=4 units to the right. So the equation is y=e . x x x 15. (a) The denominator 1+e is never equal to zero because e >0 , so the domain of f (x)=1/(1+e ) is R. 4 Stewart Calculus ET 5e 0534393217;1. Functions and Models; 1.5 Exponential Functions x x (b) 1 e =0 e =1 x x=0 , so the domain of f (x)=1/(1 e ) is ( ,0) (0, ). t 16. (a) The sine and exponential functions have domain R , so g(t)=sin (e ) also has domain R . t t t (b) The function g(t)= 1 2 has domain.
2,2 = Domain of f 1 . (c) Since f ( 2)=1 , f (1)= 2 . 21. We solve 2 Stewart Calculus ET 5e 0534393217;1. Functions and Models; 1.6 Inverse Functions and Logarithms 5 9 9 (F 32) for F : C=F 32 F= C+32 . This gives us a formula for the inverse function, that 9 5 5 is, the Fahrenheit temperature F as a function of the Celsius temperature C . F 459.67 9 9 C+32 459.67 C 491.67 C 273.15 , the domain of the inverse function. 5 5 C= 0 22. m= 2 2 m 2 2 1 v c 1.
QTR , implying that QT =TR . As the circle C shrinks, the point Q plainly approaches the origin, so the point R must approach a point 2 twice as far from the origin as T , that is, the point ( 4,0 ) , as above. 16 Stewart Calculus ET 5e 0534393217;2. Limits and Derivatives; 2.4 The Precise Definition of a Limit 1. (a) To have 5x+3 within a distance of 0.1 of 13 , we must have 12.9 5x+3 13.1 9.9 5x 10.1 1.98 x 2.02 . Thus, x must be within 0.02 units of 2 so that 5x+3 is within 0.1.
The water in the tank. In the next phase, dT /dt=0 as the water comes out at a constant, high temperature. After some time, dT /dt becomes small and negative as the contents of the hot water tank are exhausted. Finally, when the hot water has run out, dT /dt is once again 0 as the water maintains its (cold) temperature. (c) 49. In the right triangle in the diagram, let y be the side opposite angle and x the side adjacent angle . Then the slope of the tangent line is m= y/ x=tan .
(x)+g(x) 0 0.9 0.8 1.8 3.0 3.2 3.0 Extra values of x (like the value 2.5 in the table above) can be added as needed. 3 2 2 31. f (x)=x +2x ; g(x)=3x 1 . D=R for both f and g . 3 2 2 3 3 2 2 3 2 ( f +g)(x)=(x +2x )+(3x 1)=x +5x 1 , D=R . 2 ( f g)(x)=(x +2x ) (3x 1)=x x +1 , D=R . 3 2 2 5 4 3 2 ( fg)(x)=(x +2x )(3x 1)=3x +6x x 2x , D=R . f g 3 (x)= 2 x +2x 2 3x 1 , D= { x| x 1 3 } 2 since 3x 1 0 . 32. f (x)= 1+x , D=[ 1, ) ; g(x)= 1 x.